Oxymercuration–Hydration of Alkynes

Oxymercuration adds water across the C≡C triple bond of an alkyne. Step-by-step mechanism, reagents and practice.

What happens

Oxymercuration adds water across the C≡C triple bond of an alkyne. The reaction usually uses HgSO₄, H₂SO₄, and H₂O. At first, an enol is formed. The enol is unstable and quickly rearranges into a more stable ketone. For a terminal alkyne, the final product is a methyl ketone.

Reaction summary

R–C≡C–H → R–CO–CH₃ (via an enol); e.g. propyne → acetone

Reagents and conditions

Mechanism

  1. Hg²⁺ Activates the Alkyne: The alkyne is activated by Hg²⁺.
  2. Water Adds (Markovnikov): H₂O attacks, resulting in Markovnikov addition of H and OH across the triple bond: H goes to the terminal carbon and OH to the more substituted carbon.
  3. Enol Formed: An enol is formed. It is only an intermediate: you normally don't isolate it.
  4. Keto–Enol Tautomerization: The enol undergoes keto–enol tautomerization and rearranges into the more stable ketone.
  5. Product: The more stable ketone is formed: the final product, acetone. The enol was only passing through.

Selectivity

Common mistakes

Memory trick

Hg²⁺ + alkyne = Markovnikov ketone. And remember the journey: C≡C → enol → C=O. The enol is just passing through; the ketone is the final destination.

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